{"id":1041,"date":"2020-03-04T10:28:07","date_gmt":"2020-03-04T10:28:07","guid":{"rendered":"http:\/\/ibalmaths.com\/?post_type=knowledgebase&#038;p=1041"},"modified":"2020-05-28T04:18:29","modified_gmt":"2020-05-28T04:18:29","slug":"ibdp-practice-questions-binomial-theorem","status":"publish","type":"knowledgebase","link":"https:\/\/ibalmaths.com\/index.php\/ibdp-math-hl-2\/binomial-theorem\/ibdp-practice-questions-binomial-theorem\/","title":{"rendered":"Binomial Theorem &#8211; Practice Questions"},"content":{"rendered":"<p>1.\u00a0 In the expansion of \r\n<math xmlns=\"http:\/\/www.w3.org\/1998\/Math\/MathML\"><msup><mfenced><mrow><mi>a<\/mi><mo>&#8211;<\/mo><mn>3<\/mn><mi>b<\/mi><\/mrow><\/mfenced><mi>n<\/mi><\/msup><\/math>\r\n , the sum of 9<sup>th<\/sup> and 10<sup>th<\/sup> term is zero. Find the value of\u00a0 \r\n<math xmlns=\"http:\/\/www.w3.org\/1998\/Math\/MathML\"><mfrac><mi>a<\/mi><mi>b<\/mi><\/mfrac><\/math>\r\n in terms of\u00a0 \r\n<math xmlns=\"http:\/\/www.w3.org\/1998\/Math\/MathML\"><mi>n<\/mi><\/math>\r\n .<\/p>\r\n<p>2.\u00a0 If the coefficient of 4<sup>th,<\/sup> 5<sup>th<\/sup> and 6<sup>th<\/sup> terms in the expansion of\u00a0 \r\n<math xmlns=\"http:\/\/www.w3.org\/1998\/Math\/MathML\"><msup><mfenced><mrow><mn>1<\/mn><mo>+<\/mo><mi>x<\/mi><\/mrow><\/mfenced><mi>n<\/mi><\/msup><\/math>\r\n are in arithmetic sequence, then find the value(s) of \r\n<math xmlns=\"http:\/\/www.w3.org\/1998\/Math\/MathML\"><mi>n<\/mi><\/math>\r\n .<\/p>\r\n<p>3.\u00a0 If the last term in the expansion of\u00a0 \r\n<math xmlns=\"http:\/\/www.w3.org\/1998\/Math\/MathML\"><msup><mfenced><mrow><msqrt><mn>3<\/mn><mo>&#160;<\/mo><\/msqrt><mo>&#8211;<\/mo><mo>&#160;<\/mo><mfrac><mn>1<\/mn><msqrt><mn>3<\/mn><\/msqrt><\/mfrac><\/mrow><\/mfenced><mi>n<\/mi><\/msup><\/math>\r\n is \r\n<math xmlns=\"http:\/\/www.w3.org\/1998\/Math\/MathML\"><mfrac><mrow><mo>&#8211;<\/mo><msub><mi>log<\/mi><mn>2<\/mn><\/msub><mn>81<\/mn><\/mrow><msup><mn>2<\/mn><mstyle displaystyle=\"true\"><mfrac bevelled=\"true\"><mn>3<\/mn><mn>4<\/mn><\/mfrac><\/mstyle><\/msup><\/mfrac><\/math>\r\n , find the value of\u00a0 \r\n<math xmlns=\"http:\/\/www.w3.org\/1998\/Math\/MathML\"><mi>n<\/mi><\/math>\r\n .<\/p>\r\n<p>4.\u00a0 Find the remainder when\u00a0 \r\n<math xmlns=\"http:\/\/www.w3.org\/1998\/Math\/MathML\"><msup><mn>2<\/mn><mn>1003<\/mn><\/msup><\/math>\r\n is divided by 7. (Non Calculator question)<\/p>\r\n<p>5.\u00a0 If\u00a0 \r\n<math xmlns=\"http:\/\/www.w3.org\/1998\/Math\/MathML\"><msub><mi>x<\/mi><mi>n<\/mi><\/msub><mo>&#8211;<\/mo><msub><mi>y<\/mi><mi>n<\/mi><\/msub><msqrt><mn>2<\/mn><\/msqrt><mo>=<\/mo><msup><mfenced><mrow><mn>1<\/mn><mo>&#8211;<\/mo><msqrt><mn>2<\/mn><\/msqrt><\/mrow><\/mfenced><mi>n<\/mi><\/msup><\/math>\r\n \u00a0, then show that<\/p>\r\n<p>\u00a0 \u00a0 \u00a0 \u00a0<strong>a.\u00a0<\/strong> \r\n<math xmlns=\"http:\/\/www.w3.org\/1998\/Math\/MathML\"><msup><msub><mi>x<\/mi><mi>n<\/mi><\/msub><mn>2<\/mn><\/msup><mo>&#8211;<\/mo><mn>2<\/mn><msup><msub><mi>y<\/mi><mi>n<\/mi><\/msub><mn>2<\/mn><\/msup><mo>=<\/mo><msup><mfenced><mrow><mo>&#8211;<\/mo><mn>1<\/mn><\/mrow><\/mfenced><mi>n<\/mi><\/msup><\/math>\r\n<\/p>\r\n<p>6. (i) Find the first three terms in the expansion, in ascending powers of \r\n<math xmlns=\"http:\/\/www.w3.org\/1998\/Math\/MathML\"><mi>x<\/mi><\/math>\r\n , of \r\n<math xmlns=\"http:\/\/www.w3.org\/1998\/Math\/MathML\"><msup><mfenced><mrow><mn>1<\/mn><mo>&#8211;<\/mo><mn>2<\/mn><mi>x<\/mi><\/mrow><\/mfenced><mn>5<\/mn><\/msup><\/math>\r\n . [2 marks]<\/p>\r\n<p><br \/>\r\n(ii) Given that the coefficient of \r\n<math xmlns=\"http:\/\/www.w3.org\/1998\/Math\/MathML\"><msup><mi>x<\/mi><mn>2<\/mn><\/msup><\/math>\r\n in the expansion of \r\n<math xmlns=\"http:\/\/www.w3.org\/1998\/Math\/MathML\"><mfenced><mrow><mn>1<\/mn><mo>+<\/mo><mi>a<\/mi><mi>x<\/mi><mo>+<\/mo><mn>2<\/mn><msup><mi>x<\/mi><mn>2<\/mn><\/msup><\/mrow><\/mfenced><msup><mfenced><mrow><mn>1<\/mn><mo>&#8211;<\/mo><mn>2<\/mn><mi>x<\/mi><\/mrow><\/mfenced><mn>5<\/mn><\/msup><\/math>\r\n \u00a0is 12, find the value of the constant \r\n<math xmlns=\"http:\/\/www.w3.org\/1998\/Math\/MathML\"><mi>a<\/mi><\/math>\r\n . [ 3 marks]<\/p>\r\n<div id=\"link6-link-1041\" class=\"sh-link link6-link sh-hide\"><a href=\"#\" onclick=\"showhide_toggle('link6', 1041, 'Solution', 'Hide Solution'); return false;\" aria-expanded=\"false\"><span id=\"link6-toggle-1041\">Solution<\/span><\/a><\/div><div id=\"link6-content-1041\" class=\"sh-content link6-content sh-hide\" style=\"display: none;\"><\/p>\r\n<p><img loading=\"lazy\" decoding=\"async\" class=\"alignleft size-full wp-image-1822\" src=\"http:\/\/ibalmaths.com\/wp-content\/uploads\/2020\/03\/1.png\" alt=\"\" width=\"415\" height=\"306\" srcset=\"https:\/\/ibalmaths.com\/wp-content\/uploads\/2020\/03\/1.png 415w, https:\/\/ibalmaths.com\/wp-content\/uploads\/2020\/03\/1-300x221.png 300w\" sizes=\"auto, (max-width: 415px) 100vw, 415px\" \/><\/p>\r\n<p>&nbsp;<\/p>\r\n<p>&nbsp;<\/p>\r\n<p>&nbsp;<\/p>\r\n<p>&nbsp;<\/p>\r\n<p><\/div>\r\n<p>7. a) Use the binomial theorem to expand\u00a0 \r\n<math xmlns=\"http:\/\/www.w3.org\/1998\/Math\/MathML\"><msup><mfenced><mrow><mi>a<\/mi><mo>+<\/mo><msqrt><mi>b<\/mi><\/msqrt><\/mrow><\/mfenced><mn>4<\/mn><\/msup><\/math>\r\n .\u00a0<br \/>\r\nb) Hence, deduce an expression in terms of\u00a0 \r\n<math xmlns=\"http:\/\/www.w3.org\/1998\/Math\/MathML\"><mi>a<\/mi><\/math>\r\n and\u00a0 \r\n<math xmlns=\"http:\/\/www.w3.org\/1998\/Math\/MathML\"><mi>b<\/mi><\/math>\r\n for \r\n<math xmlns=\"http:\/\/www.w3.org\/1998\/Math\/MathML\"><msup><mfenced><mrow><mi>a<\/mi><mo>+<\/mo><msqrt><mi>b<\/mi><\/msqrt><\/mrow><\/mfenced><mn>4<\/mn><\/msup><mo>+<\/mo><msup><mfenced><mrow><mi>a<\/mi><mo>&#8211;<\/mo><msqrt><mi>b<\/mi><\/msqrt><\/mrow><\/mfenced><mn>4<\/mn><\/msup><\/math>\r\n .\u00a0<\/p>\r\n<div id=\"link7-link-1041\" class=\"sh-link link7-link sh-hide\"><a href=\"#\" onclick=\"showhide_toggle('link7', 1041, 'Solution', 'Hide Solution'); return false;\" aria-expanded=\"false\"><span id=\"link7-toggle-1041\">Solution<\/span><\/a><\/div><div id=\"link7-content-1041\" class=\"sh-content link7-content sh-hide\" style=\"display: none;\"><\/p>\r\n<p><img loading=\"lazy\" decoding=\"async\" class=\"alignnone size-full wp-image-1837\" src=\"http:\/\/ibalmaths.com\/wp-content\/uploads\/2020\/03\/1-1.png\" alt=\"\" width=\"412\" height=\"466\" srcset=\"https:\/\/ibalmaths.com\/wp-content\/uploads\/2020\/03\/1-1.png 412w, https:\/\/ibalmaths.com\/wp-content\/uploads\/2020\/03\/1-1-265x300.png 265w\" sizes=\"auto, (max-width: 412px) 100vw, 412px\" \/><\/p>\r\n<p>\u00a0<\/div>\r\n<p>Q8. Write down and simplify the general term in the binomial expansion of \r\n<math xmlns=\"http:\/\/www.w3.org\/1998\/Math\/MathML\"><msup><mfenced><mrow><mn>2<\/mn><msup><mi>x<\/mi><mn>2<\/mn><\/msup><mo>&#8211;<\/mo><mfrac><mi>d<\/mi><msup><mi>x<\/mi><mn>3<\/mn><\/msup><\/mfrac><\/mrow><\/mfenced><mn>7<\/mn><\/msup><\/math>\r\n, where\u00a0\r\n<math xmlns=\"http:\/\/www.w3.org\/1998\/Math\/MathML\"><mi>d<\/mi><\/math>\r\n is a constant.<br \/>\r\n(b) Given that the coefficient of \r\n<math xmlns=\"http:\/\/www.w3.org\/1998\/Math\/MathML\"><mfrac><mn>1<\/mn><mi>x<\/mi><\/mfrac><\/math>\r\nis \u221270 000, find the value of \r\n<math xmlns=\"http:\/\/www.w3.org\/1998\/Math\/MathML\"><mi>d<\/mi><\/math>\r\n.<\/p>\r\n<div id=\"link8-link-1041\" class=\"sh-link link8-link sh-hide\"><a href=\"#\" onclick=\"showhide_toggle('link8', 1041, 'Solution', 'Hide Solution'); return false;\" aria-expanded=\"false\"><span id=\"link8-toggle-1041\">Solution<\/span><\/a><\/div><div id=\"link8-content-1041\" class=\"sh-content link8-content sh-hide\" style=\"display: none;\"><\/p>\r\n<p><img loading=\"lazy\" decoding=\"async\" class=\"alignnone size-full wp-image-1890\" src=\"http:\/\/ibalmaths.com\/wp-content\/uploads\/2020\/03\/1-19.jpg\" alt=\"\" width=\"318\" height=\"420\" srcset=\"https:\/\/ibalmaths.com\/wp-content\/uploads\/2020\/03\/1-19.jpg 318w, https:\/\/ibalmaths.com\/wp-content\/uploads\/2020\/03\/1-19-227x300.jpg 227w\" sizes=\"auto, (max-width: 318px) 100vw, 318px\" \/><\/p>\r\n<p>\u00a0<\/div>\r\n<p>&nbsp;<\/p><!-- AddThis Advanced Settings generic via filter on the_content --><!-- AddThis Share Buttons generic via filter on the_content -->","protected":false},"excerpt":{"rendered":"1.\u00a0 In the expansion of a&#8211;3bn , the sum of 9th and 10th term is zero. Find the value of\u00a0 ab in terms of\u00a0 n . 2.\u00a0 If the coefficient of 4th, 5th and 6th terms in the expansion of\u00a0 1+xn are in arithmetic sequence, then find the value(s) of n . 3.\u00a0 If the [&hellip;]<!-- AddThis Advanced Settings generic via filter on get_the_excerpt --><!-- AddThis Share Buttons generic via filter on get_the_excerpt -->","protected":false},"author":4,"featured_media":0,"comment_status":"closed","ping_status":"closed","template":"","class_list":["post-1041","knowledgebase","type-knowledgebase","status-publish","hentry","knowledgebase_cat-binomial-theorem","no-wpautop"],"_links":{"self":[{"href":"https:\/\/ibalmaths.com\/index.php\/wp-json\/wp\/v2\/knowledgebase\/1041","targetHints":{"allow":["GET"]}}],"collection":[{"href":"https:\/\/ibalmaths.com\/index.php\/wp-json\/wp\/v2\/knowledgebase"}],"about":[{"href":"https:\/\/ibalmaths.com\/index.php\/wp-json\/wp\/v2\/types\/knowledgebase"}],"author":[{"embeddable":true,"href":"https:\/\/ibalmaths.com\/index.php\/wp-json\/wp\/v2\/users\/4"}],"replies":[{"embeddable":true,"href":"https:\/\/ibalmaths.com\/index.php\/wp-json\/wp\/v2\/comments?post=1041"}],"version-history":[{"count":14,"href":"https:\/\/ibalmaths.com\/index.php\/wp-json\/wp\/v2\/knowledgebase\/1041\/revisions"}],"predecessor-version":[{"id":1891,"href":"https:\/\/ibalmaths.com\/index.php\/wp-json\/wp\/v2\/knowledgebase\/1041\/revisions\/1891"}],"wp:attachment":[{"href":"https:\/\/ibalmaths.com\/index.php\/wp-json\/wp\/v2\/media?parent=1041"}],"curies":[{"name":"wp","href":"https:\/\/api.w.org\/{rel}","templated":true}]}}